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Question of the Day — 7 October 2026

JEE Physics — Electrostatics

A new free JEE practice question, picked daily. Solve it, then come back tomorrow for the next one.

Gauss's Law

Hard
5 min 75 XP3 marks

A solid sphere of radius R=3R=3 cm carries total charge QQ uniformly distributed throughout its volume. If the field at r=1r=1 cm is E1E_1 and at the surface (r=Rr=R) is E2E_2, then E2E1×3\dfrac{E_2}{E_1}\times3 equals ______.

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